Find last two digit of 6721657
WebQ: 105 = 1 1009, True False O O. A: Find the equivalent of given number then.compare. Q: Determine the units digit of 4 2874. A: Click to see the answer. Q: a. Indicate how the … WebThe last two digits of 51 456 will be 01 and the last two digits of 61 567 will be 21. Therefore, the last two digits of 51 456×61 567 will be the last two digits of 01×21= 21.
Find last two digit of 6721657
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WebSo you want to access the digits in a integer like elements in a list; easiest way I can think of is: n = 56789 lastdigit = int (repr (n) [-1]) # > 9 Convert n into a string, accessing last element then use int constructor to convert back into integer. For a Floating point number: WebJan 14, 2024 · Simpler way to extract last two digits of the number (less efficient) is to convert the number to str and slice the last two digits of the number. For example: For …
WebSep 29, 2015 · Hence the last two digits are 01. Share Cite Follow answered Sep 29, 2015 at 15:44 user249332 Add a comment 6 Hint: 7 2008 = 49 1004 = ( 50 − 1) 1004. Now expand using the binomial theorem, and notice that all terms except for the first two are multiples of 50 2, and therefore of 100. Share Cite Follow answered Sep 29, 2015 at … WebNov 22, 2014 · 1 You can always determine the last two digits of a number by calculating it modulo 4 and modulo 25. (This is an example of the Chinese remainder theorem.) Nov …
WebAug 14, 2024 · About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features NFL Sunday Ticket Press Copyright ... WebMar 2, 2024 · Now we need to calculate the sum of last two digits of numbers from ( 0!) 2 to ( 4!) 2 = 1 + 1 + 4 + 36 + 576 = 618 Therefore last two digits of the sequence are 18. 5) …
WebSolution Verified by Toppr Correct option is A) 64 236=(2 6) 236=2 1416=(2 10) 141×2 6=24 141 (24 raised to odd power) Now, those numbers which are not in the form of 2 n can …
WebApr 27, 2024 · The last digit in 2^11 = 2048 is 8 A Naive Solution is to first compute power = pow (2, n), then find the last digit in power using power % 10. This solution is inefficient and also has an integer arithmetic issue for slightly large n. An Efficient Solution is based on the fact that the last digits repeat in cycles of 4 if we leave 2^0 which is 1. the walking dead saison 6 francaisWebMay 24, 2024 · Your problem is simple and has a simple answer. In java int num = 1; is same as int num = 01; (both mean same 1 for the compiler) so when you are using % 100 with your number it returns 01 which is nothing but 1 for java as you are storing it to a double data type variable (actually when you use double in this line double digit = num % 100; it … the walking dead saison 7 streaming vfWebJan 27, 2024 · To find 17 − 2 m o d 100 we note first that 17 ⋅ 3 = 1 m o d 10. Then, we only have to solve 17 ⋅ ( 10 x + 3) = 1 m o d 100 for x ∈ [ 0, 9] ∩ Z, in order to find the inverse. Doing some computations, we find 70 x = 50 m o d 100 x = 5 solves the equation and one can verify directly that 17 ⋅ 53 = 1 m o d 100. We deduce 17 198 = 53 2 = 9 m o d 100 the walking dead saison 7 episode 8 streamingthe walking dead saison 8WebFeb 19, 2024 · Kudos. sthahvi wrote: Jai1903 wrote: ( ( 36472) 123!) ∗ ( ( 34767) 76!) Since we have to find last digit, we will find remainder when divided by 10. For ( ( 34767) 76!): 34767 fetches 7. Since we have 76! in power thus 7 2 gives 49 which gives -1 as remainder. Since 76! is multiple of 4 we get 1 as remainder. the walking dead saison 8 bande annonceWebMay 29, 2024 · This computes the last 20 digits of 2024 2024 ⋯ in an instant as 77345043177395978241. Simplified algorithm due to user Feersum: If ( a 1 mod m) ≤ 1, … the walking dead saison 7 résuméWebJun 11, 2024 · To find the last two digits of n = 5, 25, 125,..., you must consider: n − 1 mod 20 : 5 − 1 ≡ 4 ( mod 20) ⇒ 32 25 − 1 ≡ 4 ( mod 20) ⇒ 32 125 − 1 ≡ 4 ( mod 20) ⇒ 32. … the walking dead saison 8 egybest